If the sum of the digits is a multiple of 3, the whole number is divisible by 3.
7623 is divisible by 3.Test of divisibility by 3:Sum of digits of 7623 = 7+6+2+3 = 18, which is a multiple of 3, so the number is divisible by 3.If sum of the digits of a number is a multiple of 9 then it is divisible by 9.So, 7623 is also divisible by 9.Therefore, test of divisibility can help a lot in determining whether a number is divisible by any other number.
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
A number is divisible by 6 if the number is divisible by 2 AND 3.
There are different divisibility rules for different [potential] divisors.
If a number is divisible by 3 and 5, it is divisible by 15.
Divisibility by 48 requires divisibility by 3 AND by 48Divisibility by 3 requires tat the digital root (sum of digits) is divisible by 3.Divisibility by 16 requires that the number formed by the last four digits is divisible by 16.Of both these are satisfied by a number then it is divisible by 48.
If the number is even and the sum of its digits is divisible by nine then the number is divisible by 18.
a number is divisible by 9 if the sum of the digits is divisible by 9.
If a number is divisible by anything other than itself and 1, it's composite.
The rule is: if a number is divisible by 5 and 17 at the same time, that number is divisible by 85
If the number is even, it's divisible by 2.