Test of divisibility by 2:
If a number is even then the number can be evenly divided by 2.
5890 is an even number so, it is divisible by 2.
Test of divisibility by 3:
A number is divisible by 3 if the sum of digits of the number is a multiple of 3.
Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.
So, 5890 is not divisible by 3.
Test of divisibility by 6:
In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.
As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.
Test of divisibility by 9:
If the sum of digits of a number is divisible by 9 then the number is divisible by 9.
Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.
So, 5890 is not divisible by 9.
Test of divisibility by 5:
If the last digit of a number is 0 or 5, then it is divisible by 5.
It is clear that 5890 is divisible by 5.
Test of divisibility by 10:
If the last digit of a number is 0, then the number is divisible by 10.
It is clear that 5890 is divisible by 10 as the last digit is 0.
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No.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
It is evenly divisible by 2 and by 3.