Since it must be divisible by both 8 and 9, and the LCM of 8 and 9 is 72, the number must be divisible by 72. Since it is a 4 digit number, I'll assume the highest digit is not zero, so the number must be greater than 1000 and less than 10000 and divisible by 72. The first number that satisfies this is 18 x 72 = 1296. Then 19 x 72 = 1368. You can keep going and eliminate the ones with repeated digits. Here are several:
1296, 1368, 1584, 1728, 1872, 2016, 2160, 2304, 2376, 2736, 3024, 3096, ...., 9072, 9216, 9360, 9432, 9504, 9576, 9648, 9720, 9864
1008 is the lowest four-digit number divisible by 36, and 9972 is the highest.
The lowest 4-digit number that is divisible by 6 is 1002
1002 is the smallest 4 digit number divisible by 3 and 2.
They all are.
1100
6000
3333
1,002 is divisible by 6. The answer is 167.
Even numbers are divisible by two, and half of all numbers are even, so there is a 50 percent chance that a four-digit number is divisible by two.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
113 x 88 = 9944 The highest four-digit number divisible by 88 is 9944.
There can be no such number.