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If you have a right triangle with a hypotnus of 11 what is the size of the leg?
The formula for finding the length of one of the sides of a right angle triangle is a2+b2=c2, with a and b the legs and c the hypoteneus. If the triangle is Isosceles, which means that 2 of its sides are equal, the length of each leg would be aproximately 7.778184593
If perimeter is 12cm and hypoteneus is 5cm find area of right triangle?
An angle cannot have an area. It is possible, however, that the question is about a right angled triangle. Suppose the lengths of the two legs are x cm and y cm by Pythagoras, x2 + y2 = 52 = 25 and perimeter = 12 => x + y + 5 = 12 => x + y = 7 So (x + y)2 = 49 ie x2 + 2xy + y2 = 49 But x2 + y2 = 25 so 2xy = 49 - 25 = 24 So area of triangle = 0.5*xy = 24/4 = 6 sq cm
How do you find the length of one side of an isosceles triangle given the length of the other 2 sides?
For side lengths of any triangles not right angled (that would be the Hypoteneus ^2 = side A^2 + side B^2 ) there are the laws for oblique triangles. They are: 1) The law of Sines: a/ sinA = b/ sinB = c/ sinC. Once you have any 2 side measures and the accompanying angular measure (or 2 angular measures and one side measure), then treat it as a proportion. 2) The law of Cosines: a^2= b^2+c^2 - 2bc (cos a) 3) The law of Tangents: a-b/a+b= tan [1/2 (a-b)] / tan [1/2 (a+b)
If you have a right triangle with a hypotnus of 11 what is the size of the leg?
The formula for finding the length of one of the sides of a right angle triangle is a2+b2=c2, with a and b the legs and c the hypoteneus. If the triangle is Isosceles, which means that 2 of its sides are equal, the length of each leg would be aproximately 7.778184593
What will be the angle of the wrapped tape if circumference is 24cm and width is 15 cm?
The angle of tape wrapped around a circumference of 24cm, with a tape width of 15 cm is 51.3 degrees. Draw two parallel lines, 24cm apart. That is the circumference, rolled out. Draw two more parallel lines at an angle, 15cm apart, between the first two lines, with the end of one line opposite the beginning of the other. That is the tape, rolled out. Draw a 15cm line perpindicular to one of the angled lines to the other line's intersection. You have a right triangle, with hypoteneus 24cm, and side opposite an interior angle of 15cm. Sin(theta) is opposite over hypoteneus, so theta, which is the inverse sine of 15/24, is 38.7 degrees. The exterior angle, then is 90-38.7, or 51.3.
What does Pythagoras most famous proof state?
Pythagoras most famous proof is the pythagorean proof . It states that in a right angled triangle , the square of hypoteneus ( the longest side of the triangle ) is equal to the sum of squares of the other two sides .
If perimeter is 12cm and hypoteneus is 5cm find area of right triangle?
An angle cannot have an area. It is possible, however, that the question is about a right angled triangle. Suppose the lengths of the two legs are x cm and y cm by Pythagoras, x2 + y2 = 52 = 25 and perimeter = 12 => x + y + 5 = 12 => x + y = 7 So (x + y)2 = 49 ie x2 + 2xy + y2 = 49 But x2 + y2 = 25 so 2xy = 49 - 25 = 24 So area of triangle = 0.5*xy = 24/4 = 6 sq cm
How do you find the length of one side of an isosceles triangle given the length of the other 2 sides?
For side lengths of any triangles not right angled (that would be the Hypoteneus ^2 = side A^2 + side B^2 ) there are the laws for oblique triangles. They are: 1) The law of Sines: a/ sinA = b/ sinB = c/ sinC. Once you have any 2 side measures and the accompanying angular measure (or 2 angular measures and one side measure), then treat it as a proportion. 2) The law of Cosines: a^2= b^2+c^2 - 2bc (cos a) 3) The law of Tangents: a-b/a+b= tan [1/2 (a-b)] / tan [1/2 (a+b)
