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If you have a right triangle with a hypotnus of 11 what is the size of the leg?
The formula for finding the length of one of the sides of a right angle triangle is a2+b2=c2, with a and b the legs and c the hypoteneus. If the triangle is Isosceles, which means that 2 of its sides are equal, the length of each leg would be aproximately 7.778184593
If perimeter is 12cm and hypoteneus is 5cm find area of right triangle?
An angle cannot have an area. It is possible, however, that the question is about a right angled triangle. Suppose the lengths of the two legs are x cm and y cm by Pythagoras, x2 + y2 = 52 = 25 and perimeter = 12 => x + y + 5 = 12 => x + y = 7 So (x + y)2 = 49 ie x2 + 2xy + y2 = 49 But x2 + y2 = 25 so 2xy = 49 - 25 = 24 So area of triangle = 0.5*xy = 24/4 = 6 sq cm
How do you find the length of one side of an isosceles triangle given the length of the other 2 sides?
For side lengths of any triangles not right angled (that would be the Hypoteneus ^2 = side A^2 + side B^2 ) there are the laws for oblique triangles. They are: 1) The law of Sines: a/ sinA = b/ sinB = c/ sinC. Once you have any 2 side measures and the accompanying angular measure (or 2 angular measures and one side measure), then treat it as a proportion. 2) The law of Cosines: a^2= b^2+c^2 - 2bc (cos a) 3) The law of Tangents: a-b/a+b= tan [1/2 (a-b)] / tan [1/2 (a+b)
