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What is a kinematics equation that uses acceleration final velocity distance and time but not initial velocity?
Wiki User
∙ 14y ago
There is no ready equation, but you can derive one using the three known kinematic equations.
Using the general notations:
u = initial velocity
v = final velocity
a = acceleration
s = distance
t = time
v = u + at
Hence, u = v - at
v2 = u2 + 2as
Hence, substituting the value of u from above,
v2 = (v - at)2 + 2as
v2 = v2 -2vat + a2t2 + 2asÂ?
2vt = at2 + 2s Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? Â? .......(Cancelling v2 and dividing by a)
Wiki User
∙ 14y ago
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How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
Final velocity = Initial velocity +(acceleration * time)
How do you develop the general velocity equation from a Velocity vs Time graph?
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
How do Vectors and kinematics apply in medicine?
D, displacement, X=X0+V0T+0.5AT^2 V, velocity, V=V0+AT A, acceleration
If an object is accelerating what equation relates the acceleration of that object the initial velocity and the final velocity and time?
Vf = Vi + at Where Vf = final velocity Vi = initial velocity a = acceleration t = time
How do you find the initial velocity given only the distance and the time traveled?
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
What physical quantities are being studied in kinematics?
Distance, Displacement, Speed, Velocity, Acceleration.
Why the second is squared in acceleration?
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
How do you convert acceleration units to velocity units?
To convert acceleration to velocity, you must integrate.Similarly, to convert velocity to distance, you must integrate a second time. This is why the distance covered by a projectile is a second order quadratic equation.
What is rotational kinematics?
Rotational kinematics is the same as linear kinematics but with objects in rotation. All of the linear kinematic equations that you learn for velocity and acceleration can be applied to rotational kinematics except that the greek w (omega) is used for velocity and the greek a (alpha) is used for acceleration.
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
Final velocity = Initial velocity +(acceleration * time)
How to find out the velocity when acceleration and distance is given?
The equation that does involve time is.. v² = v₀² + 2ad
What is the equation for change in acceleration?
accelaration is defined as the rate of change of velocity. Therefore the formula for acceleration is a =(Final Velocity - Initial Velocity) divide by the (change in time)
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
How do you find the acceleration if time is not given?
To find the acceleration if the time is not given, you will need to know the velocity and the distance. Then, use this equation: d = vt + (1/2)at2 to solve the problem by plugging in your numbers for the distance and the velocity.
Equation for calculating velocity when acceleration and time are known?
velocity=acceleration multiplied by time
