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There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

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13 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.

The number 44 is divisible by: 2 - 44/2 = 22 4 - 44/4 = 11 The number is not divisible by 3, 5, 6, or 10.

no as 2 does not go into 15

180 is divisible by 2, 3, 4, 5, 9, and 10.

2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).

The least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.

as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

There is none. Any number that is divisible by 2 and 5, for example, must also be divisible by 10.

Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.

If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.

Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.

No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

102 is divisible by 2,3 and 6 A number is divisible by 2 if the number has even number on its unit place. A number is divisible by 3 if the sum of all the digits of the number is divisible by 3. For example= In number 102 1+0+2=3 and yes it is divisible by 3 A number is divisible by 6 if it is divisible by both 2 and 3 These laws of divisibility are applicable everywhere.

305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.

There is no such number.

It is evenly divisible by 2 and 10 but not by 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

30 30 divided by 2 is 15 30 divided by 3 is 10 30 divided by 10 is 3

Since 1845 is an odd number, it can't be divisible by 2, 6 or 10. It is divisible by 3, 5 and 9.

As 2, 3, 5 and 10 are all less than 7230 none of them are divisible by 7230. However, 7230 is divisible by 2, 3, 5 and 10; 2, 3, 5, 10 are all factors of 7230.

Here are some ways of remembering which numbers are divisible by others:Divisible by 2: Is the number even? 32 ends in a 0, 2, 4, 6, or 8, so 32 is divisible by 2Divisible by 3: Do the digits add up to be multiple of three? 3 + 2 = 5, and 5 cannot divide by 3, so 32 is NOT divisible by 3Divisible by 4: Are the last two digits divisible by 4? (For this, one has to memorize numbers between 1-100) 32 is divisible by 4Divisible by 5: Does the number end in a 5 or 0? 32 ends in a 2, so it is NOT divisible by 5Divisible by 6: Is the number divisible by 2 AND 3? (See above) 32 is not divisible by 3, so it is NOT divisible by 6Divisible by 9: Do the digits add up to be a multiple of 9? (See above) 32 is not a multiple of 3, so it is NOT divisible by 9Divisible by 10: Does the number end in a 0? 32 ends in a 2, so it is NOT divisible by 10.The answer is, 32 is divisible by 2 and 4

Any number that is divisible by both 2 and 3 is divisible by 6.

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