A number that is divisible by 2, 3, 4, 5, and 10 must be divisible by the least common multiple of these numbers, which is 60. Therefore, any number that is a multiple of 60 will be divisible by 2, 3, 4, 5, and 10. This is because 60 is the smallest number that contains all the prime factors of 2, 3, 4, 5, and 10.
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There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).
The number 30 is the smallest whole number divisible by both 10 and 6.
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Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.