441
If 21 is a factor of a number, then the factors of 21 must also be factors. So 3 and 7
3, 5 and 7 are factors of 105 15, 21, 35 and 105 are also factors of 105
prime factor = prime number which can be divided into the given number with no remainder The prime factors of 21 are 3 and 7.
No. Its factors are 3, 3, and 7.
The factors of 21 are 1, 3, 7, 21. The factors which are not a multiple of 7 are 1 and 3.
21
The prime factors of 588 are 2, 2, 3, 7, 7.
The prime factors are: 2, 3, 7
The prime factors of 147 are 3, 7 and 7. From those we can create all the other factors ... (3 x 7) and (7 x 7) which are 21 and 49. 1 is a factor of every number, and every number is a factor of itself. So all the factors of 147 are 1, 3, 7, 7, 21, 49 and 147
3*5*7=105◄
The factors for the number 63 are 1, 3, 7, 9, 21, and 63.
The factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42. The number 42 can be divided by each of these factors. Since 42 can be divided by 3 and 7, they are factors of 42.