The rule is: 0.5*(N2-3N) = number of diagonals
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A polygon with n sides has n*(n-3)/2 diagonals (not diagnols!).So, an octagon has 8*5/2 = 20 of them.
1/2*(n2-3n) where n is the number of sides of the polygon
(number of sides-2)*180 = sum of interior angles of a polygon
The number of diagnol formed by a convex polygon having N sides is {N*(N-1)/2} - N .
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides
360/exterior angle = number of sides
Using the formula: 1/2*(n2-3n) whereas 'n' is the number of sides of the polygon
The formula for finding the sum of all angles of a polygon is: N = number of sides (N-2)180 = The sum of all angles
Subtract the number of sides of the polygon by two then multiply it by 180Formula:Interior angle sum = (s-2) x 180 (With s being the number of sides the polygon has.
The correct equation for finding the number of sides for an equiangular polygon is: 180=(n-2) Shall demonstrate a sample problem if needed.