it is 10
It's divisible by three, since the sum of its digits is divisible by three. So it's composite.
Yes. 1 + 2 + 9 = 12 12 is divisible by 3. If the sum of the digits of a number are divisible by 3, then the whole number is divisible by 3. 129 is a composite number because it divisible by a factor other than 1 and itself.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
not a prime number as itβs divisible by 1, 63, 3, and 21
Nope it's Composite because the sum of digits is divisible by 3.
429 is a composite number because it is divisible by 3 in addition to 1 and itself. It is easy to tell that it is divisible by three because the sum of its digits is divisible by 3: 4 + 2 + 9 = 15.
13636131 has factors other than 1 and itself, so it is not a prime number. It is divisible by 3. (You can check this by adding the digits of the number: 1 + 3 + 6 + 3 + 6 + 1 + 3 + 1 = 24. If the sum of the digits is divisible by 3, the number itself is also divisible by 3.) Therefore, it is a composite number.
147 has factors other than 1 and itself, so it is not a prime number. For example, 147 is divisible by 3. (You can quickly check this by adding up the digits of 147: 1 + 4 + 7 = 12. If the sum of the digits is divisible by 3, so is the number.) Therefore, 147 is a composite number.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
267 is a composite number - since the digits of the number add up to a multiple of three, it is divisible by 3. Its prime factorization is 3 x 89 = 267.
If you add the digits together, you get 12. Since 12 is divisible by 3, 327 is also divisible by 3.
Answer:6003 is not a prime number. It is a composite number.Definition:A prime number has exactly two factors: 1 (also known as unity) and itself. A composite number has more than two factors; in other words, it has at least one factor besides 1 and itself.Explanation:Any number for which the digits add to a number divisible by 3 is also divisible by 3, so it also has 3 as a factor. The sum of the digits of 6003 is 6 + 0 + 0 + 3 = 9, which is divisible by 3, which means 6003 is divisible by 3. Therefore, 6003 is a composite number.