it is 10
It's divisible by three, since the sum of its digits is divisible by three. So it's composite.
Yes. 1 + 2 + 9 = 12 12 is divisible by 3. If the sum of the digits of a number are divisible by 3, then the whole number is divisible by 3. 129 is a composite number because it divisible by a factor other than 1 and itself.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
not a prime number as it’s divisible by 1, 63, 3, and 21
429 is a composite number because it is divisible by 3 in addition to 1 and itself. It is easy to tell that it is divisible by three because the sum of its digits is divisible by 3: 4 + 2 + 9 = 15.
Nope it's Composite because the sum of digits is divisible by 3.
13636131 has factors other than 1 and itself, so it is not a prime number. It is divisible by 3. (You can check this by adding the digits of the number: 1 + 3 + 6 + 3 + 6 + 1 + 3 + 1 = 24. If the sum of the digits is divisible by 3, the number itself is also divisible by 3.) Therefore, it is a composite number.
147 has factors other than 1 and itself, so it is not a prime number. For example, 147 is divisible by 3. (You can quickly check this by adding up the digits of 147: 1 + 4 + 7 = 12. If the sum of the digits is divisible by 3, so is the number.) Therefore, 147 is a composite number.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
If you add the digits together, you get 12. Since 12 is divisible by 3, 327 is also divisible by 3.
267 is a composite number - since the digits of the number add up to a multiple of three, it is divisible by 3. Its prime factorization is 3 x 89 = 267.
Answer:6003 is not a prime number. It is a composite number.Definition:A prime number has exactly two factors: 1 (also known as unity) and itself. A composite number has more than two factors; in other words, it has at least one factor besides 1 and itself.Explanation:Any number for which the digits add to a number divisible by 3 is also divisible by 3, so it also has 3 as a factor. The sum of the digits of 6003 is 6 + 0 + 0 + 3 = 9, which is divisible by 3, which means 6003 is divisible by 3. Therefore, 6003 is a composite number.