The answer to this is .... all the numbers between 999 and 10000
There are only five distinct odd digits.
There are only two digits used in binary: 0 (zero) and 1 (one).
Base two is also referred to as the binary number system.In the decimal system we use 10 different digits (0 to 9) to represent numbers. However, all numbers in binary consist of a combination of only 2 different digits; a "0" and/or a "1".All numbers can be represented using only these 2 digits.
69375
11 is the only prime number with identical digits. After 11 all numbers with identical digits can be divided by atleast 11 or 3.
Only one of those numbers has five digits: 71052 As it happens, they are all significant but it wasn't much of a choice.
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
Try the different numbers - there are only 11 after all - and multiply their digits. Or analyze the factors of the number 21.
Zero; all six digit numbers have six digits. Dude.. i m asking 6 digit numbers, containing only 4 different digits..!! e.g.:123412.. with only 2 digits repeated..!! My guess is: 10*9*8*7*4*3 but I'm also guessing that is wrong- sorry!
yes
22, 28, 82 and 88.
Numbers above 99 and under 1000 are 3-digits, all 900 of them.