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They are the multiples of 6. Since there are infinitely many of them I will not even attempt to list all of them.

Q: What is all the multiples for 2 and 3?

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They are all multiples of 6

3 multiples and they are all 2 2 * 2 * 2 = 8

All the even numbers are multiples of 2

Since all 3 are prime numbers LCM = 3 * 5 * 7 = 105 All multiples of 105 are multiples of 3, 5 and 7

Yes.

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No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.

Any and all multiples of 60.

Since 2 is a multiple of 6, all multiples of 6 are also multiples of 2.

There is an infinite number of these...

They have to be multiples of 15 so all of them will be multiples of 3. They all have to be even so you are left with 30, 60, 90

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72

3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102All the multiples of 3.

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Yes, all multiples of 9 are also multiples of 3.but they're not all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.

They're all multiples of 1, 2, 3 and 6.

6 and 12 are multiples of 2 & 3

0 The positive multiples are: 6, 12, 18 & 24. Also, all the negative multiples of 6!