They are the multiples of 6. Since there are infinitely many of them I will not even attempt to list all of them.
They are all multiples of 6
3 multiples and they are all 2 2 * 2 * 2 = 8
All the even numbers are multiples of 2
Yes.
They are all the multiples of 4.
They are all multiples of 6
Any and all multiples of 60.
There is an infinite number of these...
They have to be multiples of 15 so all of them will be multiples of 3. They all have to be even so you are left with 30, 60, 90
No, because 3 x 2 = 6
3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102All the multiples of 3.
No multiples of 2 are factors of 3.
All multiples of 8 are also multiples of 2, but not all multiples of 2 are multiples of 8.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
3 multiples and they are all 2 2 * 2 * 2 = 8
2, 4, 6 All even numbers have even multiples.
To find the common multiples of 2, 3, and 7, we first list the multiples of each number: Multiples of 2: 2, 4, 6, 8, 10, 12, ... Multiples of 3: 3, 6, 9, 12, 15, 18, ... Multiples of 7: 7, 14, 21, 28, 35, ... The first common multiple of 2, 3, and 7 is 6, as it is the smallest number that is a multiple of all three numbers. The second common multiple is 12, as it is the next number that is a multiple of all three numbers.