The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
Because it's not even. Multiples of 6 have to also be multiples of two, that is, even numbers.
The set of even natural numbers which are multiples of 3 is an empty set. This is because even numbers are divisible by 2, while multiples of 3 are not divisible by 2. Therefore, there are no numbers that satisfy both conditions simultaneously.
Any even exponent of 3 is a square number.
The first 50 multiples of 6 are the first fifty even multiples of 3.
There are 16 numbers from 1 to 101 that are divisible by 3 and are even.
It is not possible it has to be an even number.Plus it has no times or division numbers.
Multiples of 6.
16 of them.
The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
There are 16 multiples of 6 in that range.
Numbers can't be divided by multiples. They get divided by factors. Factors go into numbers, numbers go into multiples.
prime numbers can only be multiples of 1 and itself. perhaps 3 is just the number you want.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
1, 2 and 3 are the first three numbers . Multiply each of them by 2 and you will have an even multiple.
No, only every other multiple is odd. Example: 3,6,9,12,15,18
They are all even and multiples of 12, which is the lowest common multiple of 3 and 4.