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It is an inverse function of a derivative, also known as an integral.

Q: What is an antiderivative?

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35x2

I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2

(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)

The general formula for powers doesn't work in this case, because there will be a zero in the denominator. The antiderivative of 1/x is ln(x), that is, the natural logarithm of x.

Related questions

The antiderivative of 2x is x2.

The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.

35x2

Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.

I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.

Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2

The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.

(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)

-e-x + C.

It is -exp (-x) + C.

X(logX-1) + C