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Q: What is the antiderivative of 8 pi?
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What is the antiderivative of pi?

The anti-derivative of any constant c, is just c*x. Thus, the antiderivative of pi is pi*x. We can verify this by taking the derivative of pi*x, which gives us pi.


What is the antiderivative of x raised to the pi power?

x(pi+1)/(pi+1)


What is the antiderivative of 2x?

The antiderivative of 2x is x2.


What is the antiderivative of zero?

The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.


What is the antiderivative of 70x?

35x2


Which is the antiderivative of sinxcosx?

Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.


What is the antiderivative of -10x4?

I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.


Area of a section of a circle which has 8 radius if the sector has an arc that measures 45degrees?

(360/45)*Pi*8*8 = (64/8)*Pi = 8*Pi ~= 25.133


What is the antiderivative of x to the -1?

Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C


How do you take the integral from negative infinity to 4 of 1 over1 plus x2?

Recall that the antiderivative of 1/(1+x2) is arctan(x). arctan(negative infinity) = -pi/2. arctan(4) = approximately 1.325818. The answer then is arctan(4) - (pi/2) = approximately -0.244979


What is the antiderivative of x to the 1?

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2


What is the area of a circle whose circumference is 8 times pi?

c=pi*8 diameter = 8 radius = 4 area = pi * 16