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The simplified expression is 40 - 12s
16s + 4s = 20s
(4s + 1)(4s + 1) or (4s + 1)2
since A=4S then S=A/4 A is not 4S. The perimeter P is 4S. The area is S multiplied by S or S squared. therefore the side of a square is the square root of the area.
4.56
3f ( 3 only has the d orbital final ) and 2d ( 2p is the final orbital on the 2 level )
equivalent fraction of 3/4 = 6/8
If that is l and not 1 then it is 3.5l+2s when simplified
The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.
The simplified expression is 40 - 12s
.444444444444444444444444 (the 4s go on forever)
3f can not exist by the Aufbau principle, quantum mechanics and Hunds rules. In level one there is only 1s In level 2 there is 2s and 2p In level 3 there is 3s, 3p and 3d Only in level 4 and beyond is there an f shell. In level 4 there is 4s, 4p, 4d and 4f. The 4f can hold up to 14 electrons.
no 5/6s is larger than 3/4s
It can't be factored because the discriminant of the given quadratic expression is less than zero
16s + 4s = 20s
16s + 4s = 20s
4S