The expression (3f + 4s + 2f) can be simplified by combining like terms. Adding the terms with (f), we get (3f + 2f = 5f). Therefore, the equivalent expression is (5f + 4s).
The expression (4s + 2s) can be simplified by combining like terms. When you add the coefficients of (s), you get (6s). Therefore, (4s + 2s = 6s).
The simplified expression is 40 - 12s
The expression "8 4s" typically means the number 8 followed by four instances of the digit 4, which can be interpreted as 84444. The number 84444 ends with a 4, making it an even number. Therefore, 8 4s is even.
You can achieve 39 using four 4s with the following expression: ( (4 \times 4 \times 4) - 4/4 ). This simplifies to ( 64 - 1 ), which equals 39.
16s + 4s = 20s
The orbital designations 3f and 2d are invalid. The letter "f" is not used to designate orbitals, and the numbers in the designation should follow a specific order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, etc.
The expression (4s + 2s) can be simplified by combining like terms. When you add the coefficients of (s), you get (6s). Therefore, (4s + 2s = 6s).
equivalent fraction of 3/4 = 6/8
If that is l and not 1 then it is 3.5l+2s when simplified
3f can not exist by the Aufbau principle, quantum mechanics and Hunds rules. In level one there is only 1s In level 2 there is 2s and 2p In level 3 there is 3s, 3p and 3d Only in level 4 and beyond is there an f shell. In level 4 there is 4s, 4p, 4d and 4f. The 4f can hold up to 14 electrons.
The simplified expression is 40 - 12s
The expression "8 4s" typically means the number 8 followed by four instances of the digit 4, which can be interpreted as 84444. The number 84444 ends with a 4, making it an even number. Therefore, 8 4s is even.
You can achieve 39 using four 4s with the following expression: ( (4 \times 4 \times 4) - 4/4 ). This simplifies to ( 64 - 1 ), which equals 39.
.444444444444444444444444 (the 4s go on forever)
no 5/6s is larger than 3/4s
The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.
To get six 4s to make the sum of 10, you can use the following mathematical expression: (4/4) + (4/4) + (4+4) = 10. In this equation, you are dividing 4 by 4 to get 1, then adding that to another 1 from the second set of divided 4s, and finally adding the sum of the remaining two 4s to get 10.