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Q: What is an irrational number that's also an integer?

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There can be no such number.

2 times pi is not an integer. Since Pi is an irrational number, 2 pi is also an irrational number.

No, it is rational; it is also an integer.

Since pi is an irrational number, then 3pi will be an irrational also.

No, it is a real, rational number. It can also be called an integer, whole number, and natural number.

21 is an integer which is also a rational number because it can be expressed as a fraction in the form of 21/1

yeh

No, a real number could also be a rational number, an integer, a whole number, or a natural number. Irrational numbers fall into the same category of real numbers, but every real number is not an irrational number.

Actually there are more irrational numbers than rational numbers. Most square roots, cubic roots, etc. are irrational (not rational). For example, the square of any positive integer is either an integer or an irrational number. The numbers e and pi are both irrational. Most expressions that involve those numbers are also irrational.

Absolutely. Only fractions can be irrational, numerically speaking (people can also be irrational, but that's a different use of the word).

four teen is not a whole number and neither is 10 or the squareroot of 10 its also not a natural number an integer an irrational # or a real #

If you have any positive irrational number, then its negative is also irrational.

Every irrational number is a real number.

No. All irrational numbers are real, not all real numbers are irrational.

NO. pi is an irrational number, therefore, 2pi is also an irrational number/

The negative of a rational number is also rational.

The square root of 6 is an irrational number. It is also an algebraic number, a quadratic surd, an algebraic integer, a constructible number, and a computable number.

A rational number cannot also be irrational. A real number is either rational, or it is irrational.

No: Let r be some irrational number; as such it cannot be represented as s/t where s and t are both non-zero integers. Assume the square root of this irrational number r was rational. Then it can be represented in the form of p/q where p and q are both non-zero integers, ie √r = p/q As p is an integer, p² = p×p is also an integer, let y = p² And as q is an integer, q² = q×q is also an integer, let x = q² The number is the square of its square root, thus: (√r)² = (p/q)² = p²/q² = y/x but (√r)² = r, thus r = y/x and is a rational number. But r was chosen to be an irrational number, which is a contradiction (r cannot be both rational and irrational at the same time, so it cannot exist). Thus the square root of an irrational number cannot be rational. However, the square root of a rational number can be irrational, eg for the rational number ½ its square root (√½) is not rational.

The product will also be irrational.

An integer is a whole number. As 3.166666 is clearly a decimal and not a whole number, it is also not an integer.

Yes 5 is an integer and it is also a prime number

The number 71 is an integer, an odd integer, a positive odd integer, and also a prime number.

It is. A rational number is either an integer or a recurring decimal. An irrational number would be the square root of 2. There are also complex numbers that aren't rational or irrrational.

Yes.