No, it is an integer.
The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.
Yes, the square of an integer is always an integer.
The square root of an integer is a CYCLOTOMIC integer.
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
Radius of circle: 132/2pi = 21cm to the nearest integer
The cosine of 2pi is 1. In fact, for every integer N, the cosine of 2 N pi is 1.
Reciprocal of 2pi = 1/(2pi) = 0.159155(rounded)
Yes. 2*pi is irrational, pi is irrational, but their quotient is 2pi/pi = 2: not only rational, but integer.
The cos of 2pi is 360 degrees which is 1.
Because any angle increased by k*2pi radians (= k*360 degrees) where k is an integer, is, effectively, the same angle. This implies that f(x + 2kpi) = f(x) for any angle x and any trig function f. This gives f a maximum period of 2pi radians.
(pi^2+2pi)/2pi
The circumference of a circle with a 2pi radius is: 39.58
NO. pi is an irrational number, therefore, 2pi is also an irrational number/
area = 2pi*r2circumference = 2pi*rThe ratio of their circumferences will be 2pi*r1 /2pi*r2 = r1/r21) r2 = 6pi/2pi = 3. r1 = root(3).2) r = 150pi/2pi = 75. r2 = root(75)So the ratio of their circumferences isr1/r2 = root(3)/root(75)
No. 2Pi r is equal to Pi d, though.
Divide the circumference by 2PI to find the radius. ( C = 2PI*Radius)