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2 times pi is not an integer. Since Pi is an irrational number, 2 pi is also an irrational number.

Q: 2pi is an integer

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No, it is an integer.

The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.The absoluate value of a positive integer is the integer itself.

Yes, the square of an integer is always an integer.

The square root of an integer is a CYCLOTOMIC integer.

It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.

Related questions

Radius of circle: 132/2pi = 21cm to the nearest integer

The cosine of 2pi is 1. In fact, for every integer N, the cosine of 2 N pi is 1.

Reciprocal of 2pi = 1/(2pi) = 0.159155(rounded)

Yes. 2*pi is irrational, pi is irrational, but their quotient is 2pi/pi = 2: not only rational, but integer.

The cos of 2pi is 360 degrees which is 1.

Because any angle increased by k*2pi radians (= k*360 degrees) where k is an integer, is, effectively, the same angle. This implies that f(x + 2kpi) = f(x) for any angle x and any trig function f. This gives f a maximum period of 2pi radians.

(pi^2+2pi)/2pi

The circumference of a circle with a 2pi radius is: 39.58

NO. pi is an irrational number, therefore, 2pi is also an irrational number/

area = 2pi*r2circumference = 2pi*rThe ratio of their circumferences will be 2pi*r1 /2pi*r2 = r1/r21) r2 = 6pi/2pi = 3. r1 = root(3).2) r = 150pi/2pi = 75. r2 = root(75)So the ratio of their circumferences isr1/r2 = root(3)/root(75)

sec x = 2 cos x = 1/2 x = PI/3 and x=5PI/3 The period of cosine is 2PI The general solutions are: x= PI/3 + 2nPI, where n is any integer x = 5PI/3+2nPI, where n is any integer

No. 2Pi r is equal to Pi d, though.