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What is avagadro's law?

Updated: 12/10/2022
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Avogadro's Law states that equal volumes of ideal gases, at the same temperature and pressure, have the same number of particles/molecules. V/n=k where V=volume n=number of moles and k=constant

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Q: What is avagadro's law?
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Related questions

What does avagadros law say about a gas at STP?

1 mol of any gas has a volume of 22.4 L at STP


What are the molar conversions between moles and representative particles?

avagadros number


What were amedeo avagadros hobbies?

the wild thingermabober lives in peter schmaltz's ps3


How many molecules in one liter of air at 294.11 degrees Kelvin at one atmosphere of pressure?

Ideal gas law: PV=nRT. number of moles is 0.0414335 moles. x avagadros number is 2.495x1022 molecules


How many molecules are 1.94 moles?

multiply that number by avagadros number, 6.02x10^23


Units of avagadros number?

Avagadros number is 6.02 x 10^23. That is a measurement for converting representative particles or formula units to molecules.


What units do you use to measure atomic mass?

A mole (mol). You can convert to kilograms using Avagadros number.


How do you calculate atoms?

As in number? No of atoms = avagadros number (6.02X10^23) times number of mole of atoms


What is 6.0210 to the 23rd power molecules?

Avagadros number - The number of molecules/element that are found in one mole of the substance


What is the importance of avagadros number?

it is the exact number of paricles of a substance in a mole on the substance. it is also the conversoin number of amu to grams


How many grams of FeCl3 does 5.88 X1028 weigh?

I don't have a good calculator, but i'll talk you through (will actually benefit you to do it yourself, this will come back to bite you if you don't learn it). Avagadros number is no. molecules per mole. 5.88x1028 / avagadros number gives your amount of moles. Moles / molecular weight gives weight


How much is a mole?

A mole is equal to 6.022 x 1023. This number is called Avagadros number. A mole is generally abreiviated as "n".