5(c+8) or 5c+40
5c+7=23 -7 -7 5c=16 /5 /5 c= 3 & 1/5 or 16/5 thats really easy algebra 1 homework isn't it
C=7. I'll show my work. 5c-8=27. 5c=35. C=7
-5c-6=29 29 + 6= 35 -5c=35 c=7
(7 x 7) - (5 x 3)
5(c+8) or 5c+40
5c+7=23 -7 -7 5c=16 /5 /5 c= 3 & 1/5 or 16/5 thats really easy algebra 1 homework isn't it
C=7. I'll show my work. 5c-8=27. 5c=35. C=7
C - 6C + 7 = -5C + 7
-40 proof: let F = 9/5 C + 32 =C 4/5C = -32 C = -40
That is because F = 9/5 C + 32 for F and C to be the same, F = C, solve: F = C = 9/5 C +32 C -9/5 C = 32 -4/5C = 32 C = -5/4 (32) = -40 F = C = -40
The answer is usually written as:5c If you want the result as a number, that will depend on how much "c" is.
-5c-6=29 29 + 6= 35 -5c=35 c=7
The factors of 5c are 1, 5 and c 5 is a prime number.
(7 x 7) - (5 x 3)
if you mean 6-5c=-29:c=7
5c + 15= 30 - 15 -15 5c = 15 If your solving for just c..... 5c/5 = 30/5 c= 3 Hope this helps adding further your question is incomplete you must ask for the value of C, since its a arithmetic equation.