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In a triangle with vertices A, B and C and sides a, b and c where a lower case side is opposite the upper case vertex,

a^2 = b^2 + c^2 - 2*b*c*Cos(A).

The second part of the question cannot be answered since "this type of question" is not described!

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Related questions

What are the answers to law of cosines in A plus?

The law of cosines can be written in one form as: c2 = a2 + b2 - 2abCos C. Without 3 of the 4 variables being given, there is no way to answer this question.


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