If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
The sine of a complementary angle can be found using the relationship that the sine of an angle is equal to the cosine of its complement. Since the complementary angle of 28 degrees is 62 degrees (90 - 28 = 62), the sine of 62 degrees is equal to the cosine of 28 degrees. Therefore, (\sin(62^\circ) = \cos(28^\circ)).
Sine Totoo ended on 2009-02-28.
112
30. 28 x 30 = 840
28 = 1 x 28, 2 x 14, 4 x 7.
The sine of a complementary angle can be found using the relationship that the sine of an angle is equal to the cosine of its complement. Since the complementary angle of 28 degrees is 62 degrees (90 - 28 = 62), the sine of 62 degrees is equal to the cosine of 28 degrees. Therefore, (\sin(62^\circ) = \cos(28^\circ)).
cosine(28 degrees) = 0.88295 (rounded) cosine(28 radians) = -0.96261 (rounded)
Sine Totoo ended on 2009-02-28.
To find the horizontal component of the tension in the leash, you can use the cosine of the angle. The horizontal component ( F_x ) is calculated as ( F_x = F \cdot \cos(\theta) ), where ( F ) is the force (28 N) and ( \theta ) is the angle (30 degrees). Thus, ( F_x = 28 , \text{N} \cdot \cos(30^\circ) \approx 28 , \text{N} \cdot 0.866 \approx 24.9 , \text{N} ). Therefore, the magnitude of the horizontal component of the tension in the leash is approximately 24.9 N.
128
It Equals 28. If You Do 7x4 It Will Say 28.
40-n equals 28 = 12
112
30. 28 x 30 = 840
28 = 1 x 28, 2 x 14, 4 x 7.
7x4 equals 28.
28 multiplied by 30 is 840.