According to de Moivre's theorem, that for any complex number x and integer n,[cos(x) + i*sin(x)]^n = [cos(nx) + i*sin(nx)]
where i is the imaginary square root of -1.
De Morgan's theorem is used to help simplify Boolean Expressions. Digital Circuits can be simplified by the application of this theorem.
De Moivre's Theorem states that for any real number ( \theta ) and integer ( n ), the expression ( (\cos \theta + i \sin \theta)^n = \cos(n\theta) + i \sin(n\theta) ) holds. To extend this to rational indices, consider ( n = \frac{p}{q} ) where ( p ) and ( q ) are integers. We can express ( \cos \theta + i \sin \theta ) in exponential form as ( e^{i\theta} ), leading to ( (e^{i\theta})^{\frac{p}{q}} = e^{i\frac{p}{q}\theta} ). This simplifies to ( \cos\left(\frac{p}{q}\theta\right) + i \sin\left(\frac{p}{q}\theta\right) ), thus proving De Moivre's Theorem for rational indices.
(cos0 + i sin0) m = (cosm0 + i sinm0)
De Moivre's theorem states that (r cis q)n = rn cis nq, where cis x = cos x + i sin x.
de Moirve's theorem, Pascal's triangle, Pythagoras triangle, Riemann hypothesis, Fermat's last theorem. and many more
De Morgan's theorem. A and B -> not A or not B A or B -> not A and not B
He was a mathematician who contributed to the fields of calculus and algebra. His theorem an + bn = cn called, "Fermat's Last Theorem" was a challenge for the mathematical world to prove for a long time.
Yes he formed the wave-like particle theorem.
The de Moivre-Laplace theorem. Please see the link.
You would need to use de Moivre's theorem.
Pierre De Fermat is famous for Fermat's Last Theorem, which states that an+bn=cn will never be true as long as n>2
Norton's theorem is the current equivalent of Thevenin's theorem.