The rule in differentiating any bracket is: The power of the bracket multiplied by the bracket itself but lowered by one degree, then multiplied by the derivative of whatever inside the bracket. Its easy, just remember it this way. y=(1-x^3)^3 y'= 3(1-x^3)^2(-3x^2)= -9x^2(1-x^3)^2
'a' minus 'b' whole cube is equal to 'a cube' minus 'b cube' minus (3 a square b ) plus (3 a b square) . .. .....thanks
No, it is not. It is half of it.
The expression "a cube minus b cube a plus b the whole cube" can be mathematically represented as ((a^3 - b^3)(a + b)^3). The difference of cubes (a^3 - b^3) can be factored as ((a - b)(a^2 + ab + b^2)). The expression ((a + b)^3) expands to (a^3 + 3a^2b + 3ab^2 + b^3). Thus, the overall expression combines these factors, but further simplification depends on the specific context or values of (a) and (b).
The derivative of a cube function, such as ( f(x) = x^3 ), can be found using the power rule of differentiation. According to the power rule, the derivative ( f'(x) ) is given by ( 3x^{2} ). This means that the slope of the tangent line to the curve at any point ( x ) is ( 3x^{2} ). Therefore, the derivative of a cube, in this case, is ( 3x^{2} ).
hello how r u
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
(a3-b3) = (a-b) (a2+ab+b2)
A perfect cube is.
It is a perfect cube.
8i
It is a perfect cube.