The rule in differentiating any bracket is: The power of the bracket multiplied by the bracket itself but lowered by one degree, then multiplied by the derivative of whatever inside the bracket. Its easy, just remember it this way. y=(1-x^3)^3 y'= 3(1-x^3)^2(-3x^2)= -9x^2(1-x^3)^2
'a' minus 'b' whole cube is equal to 'a cube' minus 'b cube' minus (3 a square b ) plus (3 a b square) . .. .....thanks
No, it is not. It is half of it.
hello how r u
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
(a3-b3) = (a-b) (a2+ab+b2)
It is a perfect cube.
A perfect cube is.
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It is a perfect cube.
It is a perfect cube.
A perfect cube.