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The differential equation for a spring-mass system attached to one end of a seesaw can be derived from Newton's second law. If the mass ( m ) is attached to a spring with spring constant ( k ), the equation of motion can be expressed as ( m\frac{d^2x}{dt^2} + kx = 0 ), where ( x ) is the displacement from the equilibrium position. Additionally, if the seesaw is rotating, the dynamics will involve torque and may require considering angular motion, but the basic oscillatory behavior remains governed by the spring-mass dynamics. The overall system would likely result in a coupled differential equation incorporating both linear and rotational dynamics.

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2w ago

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