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F = - k x In this equation, x is the distance that the spring has been stretched or compressed away from its equilibrium position F is the restoring force exerted by the spring. k is the spring constant.
In a straight line (satisfies an equation of the form y = mx + b.)
simple pendulum center of mass and center of oscillation are at the same distance.coupled pendulum is having two bobs attached with a spring.
Pendant in a clock Swing Suspended spring with mass attached An object moving back and forth between rubber buffers along an air track
T=2pi sqrt(m/k) here,m=mass of the body which is oscillatingk=force or spring constantk=m.w2 after substituting value of k in the first equation we get,T=2pi/wand hence we can see in any case it does not depend on the mass of the body as it cancels down when we put the value of k in the equation.
smell the backside of your hand
A seesaw can be balanced with equal weight. I balanced on a ledge, so I wouldn't fall. The gymnast balanced on the beam, after a hand spring.
more mass the longer the spring
the ground
Vertical
The spring stretches when pulling force acts on it. The greater the force, the extension of the spring. The spring is attached to a pointer, which indicates the amount of force exerted on the spring
24.5 newtons per meter
A spring balance is a device wherein an object to be weighed is attached to the end of a helical spring. Gravity is a factor in using this calibrated scale.
That would depend on what style of differential you have, H-190 Differential carrier type, with independent suspension, or full axle leaf spring type. The model of car, age or even country of manufacturing, would be of help to answer this question.
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
A spring balance has a fixed spring at one end and a hook at the other. An object is attached to the hook. The weight of the object extends the spring over a calibrated scale revealing the weight of the object
A hawser. A cable. A painter. A spring. Probably others.