A number is divisible by 6 if it is divisible by 2 and 3. 54/6 = 9, 54/3 = 18, 54/2 = 27 - therefore, 54 is divisible by 6.
Is the number even and do its digits total a multiple of 3?
Yes
By tautology. If it did not work, it would not be a divisibility rule!
It is 3 6 9
A number is divisible by 6 if the number is divisible by 2 AND 3.
If the number is also divisible by 2 and 3
A number has to be even and also divisible by 3.
It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.
No Because, You Add The Digits = 4+6=10 So Its Not Check it In divisibility rules :)
144 is divisible by: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72 and 144.
The divisibility rule for 22 is that the number is divisible by 2 and by 11. Divisibility by 2 requires that the number ends in 0, 2, 4, 6 or 8. Divisibility by 11 requires that the difference between the sum of the the digits in odd positions and the sum of all the digits in even positions is 0 or divisible by 11.
3101112 is divisible by 6.