A number is divisible by 6 if it is divisible by 2 and 3. 54/6 = 9, 54/3 = 18, 54/2 = 27 - therefore, 54 is divisible by 6.
Is the number even and do its digits total a multiple of 3?
Yes
By tautology. If it did not work, it would not be a divisibility rule!
It is 3 6 9
there is a divisibility for 24 the rule is you can divide 24 as 6 and 4 i think
A number is divisible by 6 if the number is divisible by 2 AND 3.
A number has to be even and also divisible by 3.
If the number is also divisible by 2 and 3
It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
The divisibility rule for 22 is that the number is divisible by 2 and by 11. Divisibility by 2 requires that the number ends in 0, 2, 4, 6 or 8. Divisibility by 11 requires that the difference between the sum of the the digits in odd positions and the sum of all the digits in even positions is 0 or divisible by 11.
144 is divisible by: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72 and 144.