e=9...
y(t) = 3.5 - 3.5*e1-20t Then dy/dt = -3.5*e1-20t*(-20) = 70*e1-20t
In general you cannot. e2 + e1 = e*e + e = e(e + 1) which is usually not particularly helpful.
E1 stands for 2.048 Mbps E2 stands for 8 Mbps and finally E3 stands for 32 Mbps
If you mean why, that is because e1 = 0. Remember that logarithm is the inverse operation to exponentiation.
Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.
There are 63 e1's in sdh STM-1 = 63 x E1; STM-4 = 63 x 4 E1; STM-16 = 63 x 16 E1; STM-64 = 63 x 64 E1.
Differing Characteristics :-In E1 Encoding/Decoding is followed by A-Lawwhile in T1 Encoding/Decoding is followed by µ-Law.In E1 - 13 Number of Segments in Characteristicswhile in T1 - 15 Number of Segments in Characteristics.In E1 - 32 Number of Timeslots / PCM Framewhile in T1 - 24Number of Timeslots / PCM Frame.In E1 - 8 x 32 = 256 number of bits / PCM Frame while in T1 - 8 x 24 + 1* = 193 number of bits / PCM Frame. (* Signifies an additional bit).In E1 - (125µs x 8)/256 = approx 3.9µs is the length of an 8-bit Timeslot while in T1 - (125µs x 8)/193 = approx 5.2µs is the length of an 8-bit Timeslot.In E1 - 8000/s x 256 bits = 2048kbit/s is the Bit Rate of Time-Division Multiplexed Signal while in T1 - 8000/s x 193 bits = 1544kbit/s is the Bit Rate of Time-Division Multiplexed Signal.
Oh, what a happy little question! Playing the Super Mario notes on the xylophone can bring so much joy and creativity to your day. Just remember to start with the iconic melody and play around with the different notes until you find the perfect harmony that makes you smile. Happy xylophone playing, my friend!
Most likely, the E1 will not interface directly with the base transceiver. The E1 is a 2.048 MHz digitally multiplexed group of 30 E0 (8 KHz voice) channels. The base transceiver requires one or more E0 channels. You need a box in between them ... a multiplex "channel bank", which disassembles the E1 and gives you access to its constituent E0 channels.
(It's a penis) 8=====D 8 = balls D = head
E1 is carried inside C-12 container in SDH enviroment. Size of container is bigger than payload requirment of E1 in order to have clock alignment, justification opportunity bits, justification control bits, & overhead bits. C-12 container is 272 bits which multplies with 8000 (frames per second) to get data rate for one C-12 per second. Multiplying it with 63 will give you 137.088 Mbps.
8 over 8 equals 1. because 8 8ths equals 1