e=9...
y(t) = 3.5 - 3.5*e1-20t Then dy/dt = -3.5*e1-20t*(-20) = 70*e1-20t
In general you cannot. e2 + e1 = e*e + e = e(e + 1) which is usually not particularly helpful.
E1 stands for 2.048 Mbps E2 stands for 8 Mbps and finally E3 stands for 32 Mbps
If you mean why, that is because e1 = 0. Remember that logarithm is the inverse operation to exponentiation.
Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.
There are 63 e1's in sdh STM-1 = 63 x E1; STM-4 = 63 x 4 E1; STM-16 = 63 x 16 E1; STM-64 = 63 x 64 E1.
Differing Characteristics :-In E1 Encoding/Decoding is followed by A-Lawwhile in T1 Encoding/Decoding is followed by µ-Law.In E1 - 13 Number of Segments in Characteristicswhile in T1 - 15 Number of Segments in Characteristics.In E1 - 32 Number of Timeslots / PCM Framewhile in T1 - 24Number of Timeslots / PCM Frame.In E1 - 8 x 32 = 256 number of bits / PCM Frame while in T1 - 8 x 24 + 1* = 193 number of bits / PCM Frame. (* Signifies an additional bit).In E1 - (125µs x 8)/256 = approx 3.9µs is the length of an 8-bit Timeslot while in T1 - (125µs x 8)/193 = approx 5.2µs is the length of an 8-bit Timeslot.In E1 - 8000/s x 256 bits = 2048kbit/s is the Bit Rate of Time-Division Multiplexed Signal while in T1 - 8000/s x 193 bits = 1544kbit/s is the Bit Rate of Time-Division Multiplexed Signal.
Most likely, the E1 will not interface directly with the base transceiver. The E1 is a 2.048 MHz digitally multiplexed group of 30 E0 (8 KHz voice) channels. The base transceiver requires one or more E0 channels. You need a box in between them ... a multiplex "channel bank", which disassembles the E1 and gives you access to its constituent E0 channels.
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E1 is carried inside C-12 container in SDH enviroment. Size of container is bigger than payload requirment of E1 in order to have clock alignment, justification opportunity bits, justification control bits, & overhead bits. C-12 container is 272 bits which multplies with 8000 (frames per second) to get data rate for one C-12 per second. Multiplying it with 63 will give you 137.088 Mbps.
(It's a penis) 8=====D 8 = balls D = head
8 over 8 equals 1. because 8 8ths equals 1