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Q: What is 6t-2t plus 5u?

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5u + 2 = -185u = -20u = -4

r = 5k + 5ur - 5u = 5kk = r/5 - u

2u + 1 = 5u + 5 2u - 5u = 5 - 1 -3u = 4 3u = -4 u = -4/3

If you mean: 5u+10 = u+46 Then the value of u is 9

Do you mean 5u-10 = u+46? If so then:- 5u-10 = u+46 5u-u = 46+10 4u = 56 u = 14

23 + 5u = 17Subtract 17 23 from both sides:5u = -6Divide both sides by 5:u = -6/5

-5u + 4 + 8u = 43simplify by subtracting 4 from both sides of the equation to get rid of the 4 on the left:-5u + 8u = 43Simplify further by combining the -5u and the 8u:3u = 43Divide both sides by 3 to solve for u:u = 43/3rewrite the fraction:u = 14 1/3

No. It is a sum of four terms which can be simplified to a sum of three terms.

23

(9 - 5u)(9 + 5u)

3u - 5u= - 2u=====

-5x-(7x+2) She turned clockwise.

- 29 = - 4 = 5uadd 4 to each side- 29 + 4 = - 4 + 4 + 5u- 25 = 5udivide both sides integers by 5- 25/5 = (5/5)u- 5 = u========check in original equation- 29 = - 4 + 5(- 5)- 29 = - 4 - 25- 29 = - 4 + (- 25)- 29 = - 29=============checks

in the question 7-5u=-43, the answer to u is -45, because 7-5=2, 2x-45=-43. so u=-43.

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5(u-5)

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10u7 - 45u6 + 45u5 = 5u5 (2u2 - 9u + 9) = 5u5 (2u - 3) (u - 3)

P. Limagne has written: 'La .5u'

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24uv + 35u2 - 30u3 - 28v = 24uv - 28v - 30u3 + 35u2 = 4v*(6u - 7) - 5u2(6u - 7) = (4v - 5u2)*(6u - 7)

3u2-1

24u to the second power. Differentiate 40u to the fifth power which is 200u to the fourth power and 5u to the second power which is 10u. Subtract 400u to the sixth power from 1000u to the sixth power which is 600u to the sixth power. Then square 5u to the second power which is 25u to the fourth power. Finally, divide 600u to the sixth power by 25u to the fourth power. The solution is 24u to the second power. Another method is simplifying it to 8u cubed (to the third power) and taking the power rule. Take 3 times 8u which is 24u and subtract 1 from 3 in exponent which is 2. The answer is 24u to the second power.

2u4 + 38u2 = 16u3 + 24u ∴ u3 - 8u2 + 19u - 12 = 0 ∴ (u - 3)(u2 - 5u + 4) = 0 ∴ (u - 3)(u - 4)(u - 1) = 0 ∴ u ∈ {1, 3, 4} * * * Because u is a factor of both sides of the equation given, u = 0 is also a solution.

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