Distance 1 is -4 so the position is -4!
1 1/2 seconds
The work done by the force is calculated as force times distance, which is 1 newton * 2 meters = 2 joules. Power is the rate at which work is done, so in this case, power is 2 joules / 1 second = 2 watts.
When measured, this distance (from normal to peak) is considered to be 1/2 of the amplitude. Amplitude is defined as the peak-to-peak distance.
6.5cm
In the final second, the object accelerates at a constant rate of 9.8 m/s^2. Using the equation of motion, the distance fallen during the final second can be calculated as 1/2 * 9.8 * 1^2 = 4.9 meters.
Poseidon was second in command. Zeus was #1, Poseidon was #2, and Hades was #3.
2 to the second power, or (2^2), equals 4. Similarly, 1 to the second power, or (1^2), equals 1. Therefore, (2^2 = 4) and (1^2 = 1).
What is the distance between (4, -2) and (-1,6)?
Voyager 1 is the furthest and Voyager 2 is the second furthest
distance = rate*time rate = distance/time 5 miles / 3 seconds = 1 2/3 miles/second 1 2/3 miles/second * 60 seconds/minute * 60 minutes/hour = 6000 mph
Given no air resistance or other forces acting on the projectile, the projectile falls at a rate of ~9.81 meters per second. Given the position equation is at^2 + vt + x, where a is acceleration, v is velocity, x is the starting position, and t is time. Given an initial velocity and time of zero, the object will have moved ~9.81 meters in the first second.
Yes, the speed is the same in both scenarios. Speed is calculated as distance divided by time, so if you cover 10 meters in 1 second or 20 meters in 2 seconds, the speed remains constant at 10 meters per second.