(12x6)x2 = 12x8
(x-2)(x+2)= x2+2x-2x-4= x2-4
0
x3 + x = -2 => x3 + x + 2 = 0 => x3 + x2 - x2 - x + 2x - 2 = 0 => x2(x+1) - x(x+1) + 2(x+1) = 0 => (x+1)*(x2-x+2) = 0 Setting the first bracket equal to zero gives the only real solution, which is x = -1 The second bracket gives the complex roots, x = ½*[1 +or- i*sqrt(7)]
It equals x2 - 34
2x2 + x2 = 3x2
Only if x is equal to 2.
x = √(2-x) x2 = 2-x x2 + x = 2 x2 + x - 2 = 0 (x+2)(x-1) = 0 x = 1 or -2
Any monomial in the format: axn has a derivative equal to: nax(n - 1) In this case, "a" is equal to 1 and "n" is equal to 2. So the derivative of x2 is equal to 2x.
2x2=4 x2=8 x2=16 x2 = 32 and 5x5 = 25 so no, I guess not.
x2 + x2 = 2x2 2x^2
x2 + 5x - 6 can be rewritten as (x+1)(x-6). Setting each bracket = 0 gives x = -1 or x=6.
You can combine like variables but not unlike variables.So, for example, x2 * x2 = x4 but x2 * y2 does not equal xy4!Let's make x equal 2 and y equal 3 just to demonstrate this.So if x2 * x2 = x4 then 22 * 22 = 24 which would mean 4 * 4 = 16 (Yes, that's right)But x2 * y2 can not be combined. 22 * 32 = 4 * 9 = 36 (which is not equal to a combination of x and y to the power 4).