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How can the median in a set of numbers be 0?
the median is the middle in a set of numbers so if you had a set of 5 numbers like -2, -1, 0, 1, and 2 the middle number would be zero.
How you proove 1 is equal to 2?
By surreptitiously dividing by 0 in the middle of the proof.
How much is 6 - 1 x 0 2 divided by 2?
6 - 1 x 0 = 6 2 divided by 2 = 1 You have not put an operation in the middle
What is the middle line on a number line?
0 is the middle number, as below it is -1 -2 -3 -4 -5 -6 and so on, above it is 1 2 3 4 5 6, etc.
How does a number line with fractions work?
It just uses fractions instead of whole numbers. For example, if the numberline reaches between 0 and 1, the fraction 1/2 would be in the middle and 1/4 between 1/2 and 0.
What is the median number for 481059?
The median numbers are 1 and 0. This is because there is no middle number.
Where is 0.55 on a ruler?
Between '0' and '1', near the middle but a little bit closer to '1' than it is to '0'.
Where would -0.06 be on a number line?
In the middle of 0 and 1 but more near 0.
How can the median in a set of numbers be 0?
the median is the middle in a set of numbers so if you had a set of 5 numbers like -2, -1, 0, 1, and 2 the middle number would be zero.
Where is one eighth on a ruler?
Inches, I suppose. This is not normally marked by a number like "1/8". In the middle between 0 and 1 inches, there should be a line to mark 1/2 inch. In the middle between 0 and 1/2 (and also between 1/2 and 1) there are smaller marks - these are the quarter inches (1/4 and 3/4, respectively). In the middle between 0 and 1/4 is a mark that is smaller still - that is the 1/8 mark.
What is the middle number out of 2800?
Answer 1 : 8 or 0 ----- Answer 2 : 80
How you proove 1 is equal to 2?
By surreptitiously dividing by 0 in the middle of the proof.
How much is 6 - 1 x 0 2 divided by 2?
6 - 1 x 0 = 6 2 divided by 2 = 1 You have not put an operation in the middle
What is the median of these numbers 4 8 0 1 6?
Median is the middle number; set in ascending order (0, 1, 4, 6, 8). Since there is an odd number of values, it is easy to pick the middle number which is 4.
How do you get the middle value of 3 integers in Dev C plus plus?
Use the median-of-three algorithm: int min (int a, int b) { return a<b?a:b; } int max (int a, int b) { return a<b?b:a; } int median_of_three (int a, int b, int c) { return max (min (a, b), min (max (a, b), c)); } Note that the algorithm does not cater for equal values which creates a problem when any two values are equal, because there are only two values to play with, neither of which can be regarded as being the middle value. If the equal value is the lower of the two values, the largest value is returned if and only if it is the last of the three values, otherwise the lowest value is returned. But when the equal value is the larger of the two values, the largest value is always returned. Lowest value is equal: Input: 0, 0, 1 = max (min (0, 0), min (max (0, 0), 1)) = max (0, min (0, 1)) = max (0, 1) = 1 Input: 0, 1, 0 = max (min (0, 1), min (max (0, 1), 0)) = max (0, min (1, 0)) = max (0, 0) = 0 Input: 1, 0, 0 = max (min (1, 0), min (max (1, 0), 0)) = max (0, min (1, 0)) = max (0, 0) = 0 Highest value is equal: Input: 0, 1, 1 = max (min (0, 1), min (max (0, 1), 1)) = max (0, min (1, 1)) = max (0, 1) = 1 Input: 1, 0, 1 = max (min (1, 0), min (max (1, 0), 1)) = max (0, min (1, 1)) = max (0, 1) = 1 Input: 1, 1, 0 = max (min (1, 1), min (max (1, 1), 0)) = max (1, min (1, 0)) = max (1, 0) = 1 The only way to resolve this problem and produce a consistent result is to sum all three inputs then subtract the minimum and maximum values: int median_of_three (int a, int b, int c) { return a + b + c - min (min (a, b), c) - max (max (a, b), c)); } Lowest value is equal: Input: 0, 0, 1 = 0 + 0 + 1 - min (min (0, 0), 1) - max (max (0, 0), 1) = 1 - 0 - 1 = 0 Input: 0, 1, 0 = 0 + 1 + 0 - min (min (0, 1), 0) - max (max (0, 1), 0) = 1 - 0 - 1 = 0 Input: 1, 0, 0 = 1 + 0 + 0 - min (min (1, 0), 0) - max (max (1, 0), 0) = 1 - 0 - 1 = 0 Highest value is equal: Input: 0, 1, 1 = 0 + 1 + 1 - min (min (0, 1), 1) - max (max (0, 1), 1) = 2 - 0 - 1 = 1 Input: 1, 0, 1 = 1 + 0 + 1 - min (min (1, 0), 1) - max (max (1, 0), 1) = 2 - 0 - 1 = 1 Input: 1, 1, 0 = 1 + 1 + 0 - min (min (1, 1), 0) - max (max (1, 1), 0) = 2 - 0 - 1 = 1 This makes sense because when we sort 0, 0, 1 in ascending order, 0 is in the middle, while 0, 1, 1 puts 1 in the middle.
What would the median be of 1 0 4 1 1 4 and why?
You need to put these into order: 0,1,1,1,4,4 The median is the middle number. In this case where we have an even amount of scores, the median is the average of the two middle numbers. Here the two middle numbers are 1, 1. The average of these is 1. This is our median.
What is the median of 0 0 0 0 0 2 0 1?
The median of 00000201 is 0 The way to figure is out is: 1. put them into ascending order (lowest to highest) 2. cross off the each end number like this : 0 0 0 0 0 0 1 2 3. keep going : 0 0 0 0 0 0 1 2 4. if there is one number left in the middle, that's the answer, but if there's two, you divide them: so in this case, is: 0 / 0
