You normally do not have an intersection of only one set.
The intersection of a set with itself is the set itself - a statement that adds little value.
The intersection of two sets is the set which contains elements that are in each of the two sets.
Given two or more sets there is a set which is their union and a set which is there intersection. But, there is no such thing as a "union intersection set", as required for the answer to the question.
No, the set of nonregular languages is not closed under intersection.
The concept of closure: If A and B are sets the intersection of sets is a set. Then if the intersection of two sets is a set and that set could be empty but still a set. The same for union, a set A union set Null is a set by closure,and is the set A.
Its a null set.
is the result after doing intersection on 2 or more sets. It contains the elements which are common to all the sets on which intersection were done.
If B = {10111213} and C = {1213} then their intersection is the empty set, {}.The union of A with an empty set is set A.
No. It can be infinite, finite or null. The set of odd integers is infinite, the set of even integers is infinite. Their intersection is void, or the null set.
The intersection is the set of solutions that satisfy two or more mathematical expressions.
No, they do not.
Easily. Indeed, it might be empty. Consider the set of positive odd numbers, and the set of positive even numbers. Both are countably infinite, but their intersection is the empty set. For a non-empty intersection, consider the set of positive odd numbers, and 2, and the set of positive even numbers. Both are still countably infinite, but their intersection is {2}.
No, it is not.
In set theory, the symbol of intersection is ∩, like an upside down U.