Q: What is m in the problem -5 m -35?

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It is: 5*7 = 35 square m

If: 9m = 4m-35 Then: m = -7

Centi is a factor of one hundredth; therefore 35 cm is .35m. Add 5m and .35 m is 5.35m.

Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7

Therefore 5x=35, x=35/5, hence x=7

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It is: 5*7 = 35 square m

30

If: 9m = 4m-35 Then: m = -7

It is: 35 square m

Centi is a factor of one hundredth; therefore 35 cm is .35m. Add 5m and .35 m is 5.35m.

Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7

What can 5 and 7 both go into

1 m = 100 cm ⇒ 35 cm = 35/100 m = 7/20 m (divide top and bottom by 5)

Father Knows Best - 1954 Bud Has a Problem 5-35 was released on: USA: 11 May 1959

.35 m = 35 cm, and 35 cm > 31 cm. 31 cm = .31 m, and .31 m < .35 m Any way you do the math, .35 m is a greater diameter than 31 cm.

initial problem: 5*m=15 divide both sides by 5: m=(15)/(5) solution: m=3

Therefore 5x=35, x=35/5, hence x=7