It is simply: 10n
15888
yes
7*abs(n - 10) which is 7*(10 - n) if n < 10 and 7*(n - 10) if n ≥ 10
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
10 times n witch is a viatible
10n where n is positive is 10*10*10... n times [or 1 followed by n zeros] 10-n where n is positive is 1/10n = 1/(10*10*10...) n times [or 0.0...01 where there are n-1 zeros between the decimal point and the 1]
0.08
10 x n x n = 80 x n Divide by 10 x n; n = 8 Job done.
To select a committee of 3 people from 10, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 10 ) and ( k = 3 ). This gives ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 ways to select a committee of 3 people from 10.
To find the number of different seating arrangements of 10 people in 5 chairs, we can use the permutation formula ( P(n, r) = \frac{n!}{(n - r)!} ), where ( n ) is the total number of people and ( r ) is the number of chairs. Here, ( n = 10 ) and ( r = 5 ). Thus, the calculation is ( P(10, 5) = \frac{10!}{(10 - 5)!} = \frac{10!}{5!} = 10 \times 9 \times 8 \times 7 \times 6 = 30,240 ). Therefore, there are 30,240 different seating arrangements.
10000. Ten multiplied by itself n times is 1 followed by n zeros.
There are 4 terms