Pi X 5 = 15.7. Pi is equal to 3.14 then you multiply it by 5.
The area of a circle is equal to pi times the radius squared. So in your case it would be 5 squared, (25) times pi which is equal to ~78.5
circumference=pi circumference=pi circumference=pi
Since the circumference is equal to the diameter times pi, you need to divide the circumference by pi in this case.
The circumference of a circle is equal to its diameter times pi. This is also equal to two times its radius times pi.
3.14 x 3.14 = 9.8596
The area of the plate is equal to pi times the square of the radius. Since the plate has a 10 inch diameter, the radius is 5 inches. Therefore, the area is equal to pi times 25, or about 78. 5 inches.
If you mean pi then: 50 times pi is about 157 to the nearest whole number
Because 2 times the radius is equal to the diameter of the circle
Not necessarily. i times pi is not a whole number, and yet e to the power of i times pi is equal to -1.
Circumference is 2 times pi times radius, so the circumference of this circle is 2 times pi times 5, or 10 times pi. If a decimal answer is needed, pi is approximately 3.14, so C=31.4
area of a circle is equal to pi times the square of its radius.. A=(pi)r^2
No, it is not.
no, the area of a circle equals pi times the radius squared or circumference times diameter over four.
785.398163397, or, in terms of pi: 250pi
Circumference is equal to 2 times pi (3.1416) times one half of the diameter (the radius). So, if the diameter is 2 cm, then the circumference would be the product of (2) times (3.1416) times (1), or 6.2832 cm. Circumference is equal to diameter times Pi. c = Pi * d diameter times pi
Approximately 50.26m, because circumference is equal to diameter times pi (or 3.1415). Or twice the radius times pi.
3.141592654 * 5 = 15.70796327
40pi is equal to about 124.
Approximately yes. Circumference is equal to pi times the diameter of the circle, which is 3.14159 times the diameter.
Since the circumference of a circle is equal to its diameter times pi, the o.d. of a pipe is equal to its exterior circumference divided by pi.