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Q: What is prime factorization of 198 using exponets?

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As a product of its prime factors: 198 = 2*32*11

The prime factorization of 198 is: 2 x 32 x 11 = 198

2 x 32 x 11 = 198

The prime factorization is: 2 x 3 x 3 x 11 = 198

198 = 2 * 3 * 3 * 11

198 99,2 33,3,2 11,3,3,2

As a product of its prime factors: 2*3*3*11 = 198

198 = 2*3*3*11

You need at least two numbers to find a GCF.

It is: 2*3*3*11 = 198 or as 2*32*11 =198

the answer is 12 you can find the answer by making factor trees and multiplying the similar prime numbers.

To find the prime factorization start with any two factors of 198 and keep factoring the composite factors until all factors are prime. 198 2 x 99 2 x 3 x 33 2 x 3 x 3 x 11 = 198

No - since 9 is not a prime number, it would be reduced even further. The prime factorization in question would be equal to 2 x 32 x 11 = 198.

198 = 2 x 3² x 11 = 2 x 3 x 3 x 11 For a table of the prime factorisation of all integers up to 1000, see the related link, "Table of Prime Factorizations".

2 x 3 x 3 = 18 2 x 11 = 22 2 x 3 x 3 x 11 = 198, the LCM

198 is a composite number.

198 = 2 * 3 * 3 * 11

Composite.

132 = 2 * 2 * 3 * 11 = 22 * 3 * 11198 = 2 * 3 * 3 * 11 = 2 * 32 * 11

It is: 2*3*3*11 = 198

It is: 2*3*3*11 = 198

2 x 2 x 3 x 11 = 132 2 x 3 x 3 x 11 = 198

The prime numbers between 180 and 198 are 181, 191, 193, and 197.

198 is composite because it has three or more factors.

198 = 2 Ã— 32 Ã— 11198 = 2 x 3 x 3 x 11