sqrt(6x + 1) = (x - 1)
Square each side of the equation:
6x + 1 = (x - 1)2
6x + 1 = x2 - 2x + 1
Subtract 6x from each side:
1 = x2 - 8x + 1
Subtract 1 from each side:
x2 - 8x = 0
Factor the left side:
x (x - 8) = 0
This equation is true if [ x = 0 ] and also if [ x = 8 ]. We'll have to check
both of them and see if they solve the original equation.
Check (x = 0) :
sqrt(6x + 1) = sqrt(1) = +1 or -1
(x - 1) = (0 - 1) = -1 yay!
Check (x = 8) :
sqrt(6x + 1) = sqrt(48 + 1) = sqrt(49) = +7 or -7
(x - 1) = (8 - 1) = 7 yay!
Both (x = 0) and (x = 8) make the original equation a true statement,
so those are your solutions.
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