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sqrt(6x + 1) = (x - 1)

Square each side of the equation:

6x + 1 = (x - 1)2

6x + 1 = x2 - 2x + 1

Subtract 6x from each side:

1 = x2 - 8x + 1

Subtract 1 from each side:

x2 - 8x = 0

Factor the left side:

x (x - 8) = 0

This equation is true if [ x = 0 ] and also if [ x = 8 ]. We'll have to check

both of them and see if they solve the original equation.

Check (x = 0) :

sqrt(6x + 1) = sqrt(1) = +1 or -1

(x - 1) = (0 - 1) = -1 yay!

Check (x = 8) :

sqrt(6x + 1) = sqrt(48 + 1) = sqrt(49) = +7 or -7

(x - 1) = (8 - 1) = 7 yay!

Both (x = 0) and (x = 8) make the original equation a true statement,

so those are your solutions.

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