Its total surface area is 15614 square feet.
Volume of a cylindrical tank 8 feet in diameter and 8 feet tall is pi x 16 square feet (radius squared) x 8 feet (height) = 402 cubic feet.
The square footage is the footprint: length times width. 7521 square feet.
To get the area you multiply the length and the width. Doing the math gives an answer of 2,560 square feet.
If you are looking for the square footage of the room, the height shouldn't make a difference. So the square footage would just be 10 ft x 10 ft = 100 square feet. If you are looking for surface area of all the walls, floor, and ceiling, that would be 100+100+80+80+80+80 = 520 square feet If you're looking for the cubic footage of the room, then you would use all three dimensions. 8ft x 10ft x 10ft = 800 cubic feet.
The answer depends on whether the shape is a cylinder of a cone (or something else).
the square
Floor and ceiling = (9 x 8) = 72 square feet each Two walls = (9 x 7) = 63 square feet each Other two walls = (8 x 7) = 56 square feet each Total area on all six surfaces inside the room = 382 square feet
The height of the room doesn't matter, so it's just the length times the width, or 21 x 15.
You cannot. Height is a one-dimensional measurement. Square feet are two-dimensional. To get from height to square feet you must include another dimension... usually width. I am 6 feet tall - that is my height..... I don't have square footage, and my height cannot be converted to square feet. However, the door of the room I'm in is 6 feet 6 inches high, and is 3 feet 6 inches wide - which tells me that the surface area of the door is 22.75 square feet.
The question is mis-specified. You ask for the area but give the dimensions for volume.
2 feet
A square will always be larger than a circle with the same diameter. Draw a square, then draw a circle that fits inside the square exactly (that is, each of the four points shared by the two shapes exactly bisect each line of the square). The square contains the entire circle, plus all the extra area in the corners.