Q: What is te prime factorization of 248?

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The prime factorization of 248 is 2 x 2 x 2 x 31 or 2^3*31

2 x 2 x 2 x 31 = 248

248 = 2 x 2 x 2 x 31

249 = 3 x 83

248 = 23 × 31

3 x 3 x 5

..2 | 248 ..2 | 124 ..2 | 62 31 | 31 .... | 1 ⇒ 248 = 2 x 2 x 2 x 31 = 23 x 31

248 Divide by two. 124,2 Divide by two. 62,2,2 Divide by two. 31,2,2,2 Stop. All the factors are prime. 2 x 2 x 2 x 31 = 248

248 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 248 are 1, 2, 4, 8, 31, 62, 124, and 248.The factor pairs of 248 are 1 x 248, 2 x 124, 4 x 62, and 8 x 31.The proper factors of 248 are 1, 2, 4, 8, 31, 62, and 124 or,if the definition you are using excludes 1, they are 2, 4, 8, 31, 62, and 124.The prime factors of 248 are 2, 2, 2, and 31. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors (listing each prime factor only once) of 248 are 2 and 31.The prime factorization of 248 is 2 x 2 x 2 x 31 or, in exponential form, 23 x 31.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common. Factor tree:24862 431 2 2 2The prime factors of 248 are 2, 2, 2, and 31.The prime factorization of 248 is 2 x 2 x 2 x 31, which can also be represented as 23 x 31.

2 x 2 x 2 x 2 = 16

2 x 2 x 3 x 5 = 60

When all the factors are prime numbers, that's a prime factorization.