If I understand the question correctly, you simply have to calculate: 15 x 0, 15 x 1, 15 x 2, etc.
1 x 75, 3 x 25, 5 x 15.
15... if vv is x, then x + v = 15 if you know your 5 times table then count it. 5 10 15....so 15 is the answer.
1 x 165, 3 x 55, 5 x 33, 11 x 15.
The multiples of 15 are numbers that can be evenly divided by 15. They include 15, 30, 45, 60, 75, and so on.
If I understand the question correctly, you simply have to calculate: 15 x 0, 15 x 1, 15 x 2, etc.
1 x 75, 3 x 25, 5 x 15.
No, forty is not in the three times table
15... if vv is x, then x + v = 15 if you know your 5 times table then count it. 5 10 15....so 15 is the answer.
1 x 165, 3 x 55, 5 x 33, 11 x 15.
I assume we are talking single-valued functions. If this is the case, any table with values for the function, you just have to look at the inputs to make sure two of them are not the same (in elementary algebra classes this is referred to as the "Vertical Line Test"). For example, say we have a table of numbers x and y: x | y ------ 10|15 12|15 This is a function because all the x values are different. Likewise we can say that were the table: x | y ------ 15|10 15|12 it would not be a function because we have multiple outputs originating from a single input.
There are three ways to get to 75. There is 75 x 1 3 x 25 and 5 x 15
The multiples of 15 are numbers that can be evenly divided by 15. They include 15, 30, 45, 60, 75, and so on.
In the 3x table 5 is prime (3 x 5 = 15), 7 is prime (3 x 7 = 21), and 11 is prime (3 x 11 = 33).
Yes, I can.
There are many possibilities, but the simplest answer is y = 10 - x
(15/100)x = 15 x = 15/(15/100) x = 15(100/15) x = 1500/15 x = 100