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What is the 7th term in the geometric sequence in which a10 is 9 and a13 is -72?
Wiki User
∙ 10y ago
a7/a10 = a10/a13 = 1/r3 where r is the common ratio.
So a7 = (a10)2/a13 = -81/72 = -9/8
Wiki User
∙ 10y ago
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