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What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
Wiki User
∙ 7y ago
End points: (10, -4) and (2, 2)
Midpoint: (6, -1) which is the centre of the circle
Distance from (6, -1) to any of its end points = 5 which is the radius
Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
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∙ 7y ago
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What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the equation of a circle whose diameter end points are at 2 -3 and 8 7 on the Cartesian plane?
Diameter endpoint's: (2, -3) and (8, 7) Midpoint: (5, 2) which is the centre of the circle Distance from (5, 2) to (2, -3) or (8, 7) = square root of 34 which is the radius Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What of a circle is a chord that has the center of the circle as one of its points?
The diameter of the circle.
What is a line segment that contains 2 points on a circle?
It is a chord and the largest chord in a circle is its diameter
What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the equation and area of a circle whose diameter end points are at 2 -3 and 8 7 on the Cartesian plane showing work?
Diameter end points: (2, -3) and (8, 7) Centre of circle: (5, 2) Length of diameter: 2 times square root of 34 Equation: (x-5)^2+(y-2)^2 = 34 which in effect is the radius squared Area in square units: 34*pi
What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
What is the equation of a circle whose diameter end points are at 2 -3 and 8 7 on the Cartesian plane?
Diameter endpoint's: (2, -3) and (8, 7) Midpoint: (5, 2) which is the centre of the circle Distance from (5, 2) to (2, -3) or (8, 7) = square root of 34 which is the radius Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What of a circle is a chord that has the center of the circle as one of its points?
The diameter of the circle.
what are endpoints on the diameter?
The points where a diameter intersects the circle are its endpoints.
What is the equation of the line whose end points are 5 2 and 3 2 on the Cartesian plane?
The equation is y = 2
What is a line segment that contains 2 points on a circle?
It is a chord and the largest chord in a circle is its diameter
What is a segment from two points on a circle which passes through the center of the circle?
It is the circle's diameter
What is the radius of a circle and its equation when its diameter touches the points of 2 -3 and 8 7 on the Cartesian plane showing key stages?
Points: (2, -3) and (8, 7) Centre: (8+2)/2 and (7-3)/2 = (5, 2) Radius: (8-5)2+(7-2)2 = 34 and the square root of this is the radius Equation: (x-5)2+(y-2)2 = 34
What is the centre and radius of a circle enscribed through the points of 6 2 and 8 -2 and 0 2 on the Cartesian plane?
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
