The cord of a circle that contains the center of that circle is a diameter of that circle.
4.25 inches
the answer is 20
L=L(initial)[1+C(al)]*T =1.184cm I can't figure out the second one either
Center
CD's have a diameter of 5.5 centimeters;)
15 mm
The center of the rim is 66.1mm in diameter on a 2005-2008 Nissan Frontier.
The diameter is 0.286". Which, by the way, does not correspond to any standard size drill in English or metric units, but that's what it is. If there is an explanation for this I haven't seen it.
18mm It was decided in a meeting by someone putting a coin from the Netherlands on the table and said that size would do.
4.24563 inches is the diameter of a golf hole.
It is 6 inches in diameter located in the center of the board and 9 inches from the top of the board to the center of the hole. For cornhole board design ideas check out: http://www.cornholeace.com/cornhole-board-designs.php
The cord of a circle that contains the center of that circle is a diameter of that circle.
The "diameter" of a black hole is usually taken as the diameter of the event horizon.
There is no such hole.
The diameter is usually considered the diameter of the event horizon. The diameter of this event horizon is directly proportional to the black hole's mass. More information at http://en.wikipedia.org/wiki/Schwarzschild_radiusThe diameter is usually considered the diameter of the event horizon. The diameter of this event horizon is directly proportional to the black hole's mass. More information at http://en.wikipedia.org/wiki/Schwarzschild_radiusThe diameter is usually considered the diameter of the event horizon. The diameter of this event horizon is directly proportional to the black hole's mass. More information at http://en.wikipedia.org/wiki/Schwarzschild_radiusThe diameter is usually considered the diameter of the event horizon. The diameter of this event horizon is directly proportional to the black hole's mass. More information at http://en.wikipedia.org/wiki/Schwarzschild_radius
Diameter: 2*6 = 12 inches