18 = 2 * 3 * 370 = 2 * 5 * 7Thus:LCM = 2*3*3*5*7 = 630HCF = 2
You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12
16 48 = 2^4 x 3 224 = 2^5 x 7 hcf = 2^4 = 16
The GCF is 42.
The GCF is 1.
The HCF of 165 and 210 is 15. The LCM is 2310.
hcf(14, 30) = 2 lcm(14, 30) = 210 14 = 2 x 7 30 = 2 x 3 x 5 hcf = 2 lcm = 2 x 3 x 5 x 7 = 210
18 = 2 * 3 * 370 = 2 * 5 * 7Thus:LCM = 2*3*3*5*7 = 630HCF = 2
hcf = 15 lcm = 3510 270 = 2 x 33 x 5 195 = 3 x 5 x 13 hcf = 3 x 5 = 15 lcm = 2 x 33 x 5 x 13 = 3510
They are 9 and 6
4=2^2 5=5^0 6=3^0,2^0 Then,2^03^05^0=111=1
You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF
Factor them. 2 x 2 x 2 x 3 = 24 2 x 3 x 5 = 30 Select the common factors. 2 x 3 = 6, the GCF.
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
The HCF of the given numbers is 1