Q: What is the L.C.M. of two numbers if there h.c.f. is 15?

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2 and 15 3 and 10 5 and 6

To find the LCM of two numbers, you first split them into their prime factors: 30 = 2x3x5 75 = 3x5x5 Next you need to work out the HCF. Here, the HCF will be 3x5 = 15. Finally, you multiply the numbers together and divide by the HCF. 30x75/15 = 150. Therefore the LCM of 30 and 75 is 150.

Factors: 15 = 3 x 5, 18 = 2 x 3 x 3. The LCM of two numbers = their product divided by their HCF. In this instance the product is 270 and the HCF is 3 so the LCM is 90.

hcf(5, 15) = 5 lcm(5, 15) = 15.

The LCM of 3, 15 and 36 is 180.

No.-------------------------------------------------------------To find the HCF and LCM of two (or more) numbers list the numbers in their prime factorisations in power format; then:HCF = product of the primes to the LOWEST power across all the numbers;LCM = product of the primes to the HIGHEST power across all the numbers.Note: for p being any prime, p⁰ = 1; so if a prime does not appear as a factor of a number, it can be said to have a power of 0. This means that the LOWEST power is 0 and the prime does not appear in the HCF of the numbers. The HIGHEST power of a prime must be at least the LOWEST power of a prime.Thus if a prime appears in the HCF of the numbers (with a power greater than or equal to 1) it MUST also appear in the LCM of the numbers.If the HCF of some numbers is 15, then: 15 = 3 × 5 which means that the primes 3 and 5 MUST both apear in the LCM.But 175 = 5² × 7, which does NOT include 3, so 175 CANNOT be the LCM of some numbers which have a HCF of 15.

9 & 15

Any two numbers that have a common factor greater than 1 will have a LCM less than their product, eg: LCM(10, 15) = 30 < 10 x 15 = 150 (since HCF(10, 15) = 5) LCM(6, 10) = 30 < 6 x 10 = 60 (since HCF(6, 10) = 2) LCM(18, 27) = 54 < 18 x 27 = 486 (since HCF(18, 27) = 9)

1, 15, 105

5 and 75 15 and 25

HCF is the highest common factor of two or more numbers. HCF of 9 and 15 is 3.

4

HCF(315, 195) = 15 LCM(315, 195) = 4095

To find the HCF you first need to break the numbers down into their prime factors. In this case we have: 30 = 2x3x5 45 = 3x3x5 The next step is to identify any common factors. In this case both numbers have 3 and 5 as prime factors. To find the HCF, multiply these together: 3x5 = 15. To get the LCM, multiply the numbers together then divide by the HCF: 30x45/15 = 90.

5 and 60 15 and 20

An HCF of 1 means that the two numbers share no prime factors. An LCM of 30, means the numbers have between them prime factors of 2, 3 and 5. Thus any product combination of these factors will give a possible answer. You could have: 2 and 3x5 (15) 3 and 2x5 (10) or 5 and 2x3 (6)

Shell program to find LCM and hcf of two no.s tput clear echo "Enter first no" read a echo "Enter 2nd no" read b p= 'expr $a \* $b' while [$b -ne 0] do r= 'expr $a % $b' a=$b b=$r done LCM = 'expr $p / $a' echo "LCM = $LCM" echo "Hcf = $a"

In these types of problems, the numbers can also be the answer. 3 and 30 have a GCF of 3 and an LCM of 30. Since the product of the GCF and LCM of two numbers is the same as the product of the numbers, you could also use another factor pair of 90, like 6 and 15.

30 & 1. 15 & 2. 10 & 3.

You need at least two numbers to find an LCM.

You need at least two numbers to find an LCM.

The LCM of the given two numbers is: 13,710

The HCF is the largest number that both numbers can be divided by. If the HCF is 1, that would suggest that the two numbers share no prime factors. Thus, any two numbers which are coprime will have an HCF of 1. Consecutive numbers are good examples here - 15 and 16, 27 and 28, 104 and 105, all have an HCF of 1.

One. In fact, the least common factor of any two counting numbers is one.

You need at least two numbers to find a GCF.