2 x 2 x 2 = 8
2 x 2 x 2 x 7 = 56
2 x 2 x 2 x 7 = 56, the LCM
To find the Least Common Multiple (LCM) of 98, 56, and 28, we first need to find the prime factorization of each number. The prime factorization of 98 is 2 * 7^2, the prime factorization of 56 is 2^3 * 7, and the prime factorization of 28 is 2^2 * 7. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers. Therefore, the LCM of 98, 56, and 28 is 2^3 * 7^2, which equals 392.
Prime factorization of 7 = 7 Prime factorization of 56 = 2*2*2*7 Common number(factor in factorization) or simply H.C.F.= 7 L.C.M. = H.C.F. * Product of other numbers = 7*2*2*2 = 56 In this case 7 is an exact divisor of 56, therefore L.C.M. = 56
56 prime factorization 2*2*2*7 exponents: 23*7 * = multiply
23 x 71 = 56
The prime factorization of 56 is:7 x 23 = 56
23 x 7 = 56
It is: 4
whats continuous divisions of 56
To find the Least Common Multiple (LCM) of 56, 72, and 104, we first need to find the prime factorization of each number. The prime factorization of 56 is 2^3 * 7, the prime factorization of 72 is 2^3 * 3^2, and the prime factorization of 104 is 2^3 * 13. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers: 2^3 * 3^2 * 7 * 13 = 6552. Therefore, the LCM of 56, 72, and 104 is 6552.
1
2 x 2 x 2 = 8 2 x 7 = 14 2 x 2 x 2 x 7 = 56, the LCM
28 x 56 = 4,000,000