b3c2
bcd
Make them additive for convenience.4s3 + 36s2factor out 4s24s2(s + 9)---------------4s2====LCM
LCM(17, 13, 2) = 442
The LCM of the given three numbers is 570
The LCM of the given three numbers is 14
The LCM of the given three numbers is 12
12b2c3
The Least Common Multiple (LCM) of 2 and 8 is 8.
Determine the prime factors of all three numbers. 8 = 2 x 2 x 2 = 23 16 = 2 x 2 x 2 x 2 = 24 22 = 2 x 11 The LCM is the product of the highest power of each prime factor. The highest power of 2 is 24 = 16 The highest power of 11 is just 11 (technically it is 111 but this equals 11) The LCM is therefore 16 x 11 = 176.
The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
2 x 33 = 54 That's one number. You need at least two to find an LCM.
LCM is 36, which is the multiple of the highest power of prime factors in the given numbers (2^2 x 3^2).