LCM(a2b5, a3b3)
The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
Their product.
That's one term. You need at last two to find an LCM. That factors to t(t + 2)(t + 2)
Thirty-five is the LCM of 3/5 + 6/7.
The LCM is 392.
LCM of 15 and 2 is 30.
a3*b3 = a3b3
The LCM of 12 and 30 is 60.
The LCM is r^3 + 9r^2 - 25r - 225.
60
To find the least common multiple (LCM) of two terms, we need to identify the highest power of each unique factor present in both terms. In this case, the LCM of a³b² and a²b⁵ would be a³b⁵, as it includes the highest power of both 'a' and 'b' present in either term. Therefore, the LCM of a³b² and a²b⁵ is a³b⁵.
x2 + 48x + 320
6y3 + 48y2 + 90y
The LCM is x^2 - 1.
60
Their product.
That's one term. You need at last two to find an LCM. That factors to t(t + 2)(t + 2)
Thirty-five is the LCM of 3/5 + 6/7.